Optimal. Leaf size=275 \[ -\frac{2 a^2 b^2 \cos ^3(c+d x)}{d}+\frac{12 a^2 b^2 \cos (c+d x)}{d}+\frac{6 a^2 b^2 \sec (c+d x)}{d}-\frac{4 a^3 b \sin ^3(c+d x)}{3 d}-\frac{4 a^3 b \sin (c+d x)}{d}+\frac{4 a^3 b \tanh ^{-1}(\sin (c+d x))}{d}+\frac{a^4 \cos ^3(c+d x)}{3 d}-\frac{a^4 \cos (c+d x)}{d}+\frac{10 a b^3 \sin ^3(c+d x)}{3 d}+\frac{10 a b^3 \sin (c+d x)}{d}+\frac{2 a b^3 \sin ^3(c+d x) \tan ^2(c+d x)}{d}-\frac{10 a b^3 \tanh ^{-1}(\sin (c+d x))}{d}+\frac{b^4 \cos ^3(c+d x)}{3 d}-\frac{3 b^4 \cos (c+d x)}{d}+\frac{b^4 \sec ^3(c+d x)}{3 d}-\frac{3 b^4 \sec (c+d x)}{d} \]
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Rubi [A] time = 0.247616, antiderivative size = 275, normalized size of antiderivative = 1., number of steps used = 19, number of rules used = 8, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.381, Rules used = {3517, 2633, 2592, 302, 206, 2590, 270, 288} \[ -\frac{2 a^2 b^2 \cos ^3(c+d x)}{d}+\frac{12 a^2 b^2 \cos (c+d x)}{d}+\frac{6 a^2 b^2 \sec (c+d x)}{d}-\frac{4 a^3 b \sin ^3(c+d x)}{3 d}-\frac{4 a^3 b \sin (c+d x)}{d}+\frac{4 a^3 b \tanh ^{-1}(\sin (c+d x))}{d}+\frac{a^4 \cos ^3(c+d x)}{3 d}-\frac{a^4 \cos (c+d x)}{d}+\frac{10 a b^3 \sin ^3(c+d x)}{3 d}+\frac{10 a b^3 \sin (c+d x)}{d}+\frac{2 a b^3 \sin ^3(c+d x) \tan ^2(c+d x)}{d}-\frac{10 a b^3 \tanh ^{-1}(\sin (c+d x))}{d}+\frac{b^4 \cos ^3(c+d x)}{3 d}-\frac{3 b^4 \cos (c+d x)}{d}+\frac{b^4 \sec ^3(c+d x)}{3 d}-\frac{3 b^4 \sec (c+d x)}{d} \]
Antiderivative was successfully verified.
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Rule 3517
Rule 2633
Rule 2592
Rule 302
Rule 206
Rule 2590
Rule 270
Rule 288
Rubi steps
\begin{align*} \int \sin ^3(c+d x) (a+b \tan (c+d x))^4 \, dx &=\int \left (a^4 \sin ^3(c+d x)+4 a^3 b \sin ^3(c+d x) \tan (c+d x)+6 a^2 b^2 \sin ^3(c+d x) \tan ^2(c+d x)+4 a b^3 \sin ^3(c+d x) \tan ^3(c+d x)+b^4 \sin ^3(c+d x) \tan ^4(c+d x)\right ) \, dx\\ &=a^4 \int \sin ^3(c+d x) \, dx+\left (4 a^3 b\right ) \int \sin ^3(c+d x) \tan (c+d x) \, dx+\left (6 a^2 b^2\right ) \int \sin ^3(c+d x) \tan ^2(c+d x) \, dx+\left (4 a b^3\right ) \int \sin ^3(c+d x) \tan ^3(c+d x) \, dx+b^4 \int \sin ^3(c+d x) \tan ^4(c+d x) \, dx\\ &=-\frac{a^4 \operatorname{Subst}\left (\int \left (1-x^2\right ) \, dx,x,\cos (c+d x)\right )}{d}+\frac{\left (4 a^3 b\right ) \operatorname{Subst}\left (\int \frac{x^4}{1-x^2} \, dx,x,\sin (c+d x)\right )}{d}-\frac{\left (6 a^2 b^2\right ) \operatorname{Subst}\left (\int \frac{\left (1-x^2\right )^2}{x^2} \, dx,x,\cos (c+d x)\right )}{d}+\frac{\left (4 a b^3\right ) \operatorname{Subst}\left (\int \frac{x^6}{\left (1-x^2\right )^2} \, dx,x,\sin (c+d x)\right )}{d}-\frac{b^4 \operatorname{Subst}\left (\int \frac{\left (1-x^2\right )^3}{x^4} \, dx,x,\cos (c+d x)\right )}{d}\\ &=-\frac{a^4 \cos (c+d x)}{d}+\frac{a^4 \cos ^3(c+d x)}{3 d}+\frac{2 a b^3 \sin ^3(c+d x) \tan ^2(c+d x)}{d}+\frac{\left (4 a^3 b\right ) \operatorname{Subst}\left (\int \left (-1-x^2+\frac{1}{1-x^2}\right ) \, dx,x,\sin (c+d x)\right )}{d}-\frac{\left (6 a^2 b^2\right ) \operatorname{Subst}\left (\int \left (-2+\frac{1}{x^2}+x^2\right ) \, dx,x,\cos (c+d x)\right )}{d}-\frac{\left (10 a b^3\right ) \operatorname{Subst}\left (\int \frac{x^4}{1-x^2} \, dx,x,\sin (c+d x)\right )}{d}-\frac{b^4 \operatorname{Subst}\left (\int \left (3+\frac{1}{x^4}-\frac{3}{x^2}-x^2\right ) \, dx,x,\cos (c+d x)\right )}{d}\\ &=-\frac{a^4 \cos (c+d x)}{d}+\frac{12 a^2 b^2 \cos (c+d x)}{d}-\frac{3 b^4 \cos (c+d x)}{d}+\frac{a^4 \cos ^3(c+d x)}{3 d}-\frac{2 a^2 b^2 \cos ^3(c+d x)}{d}+\frac{b^4 \cos ^3(c+d x)}{3 d}+\frac{6 a^2 b^2 \sec (c+d x)}{d}-\frac{3 b^4 \sec (c+d x)}{d}+\frac{b^4 \sec ^3(c+d x)}{3 d}-\frac{4 a^3 b \sin (c+d x)}{d}-\frac{4 a^3 b \sin ^3(c+d x)}{3 d}+\frac{2 a b^3 \sin ^3(c+d x) \tan ^2(c+d x)}{d}+\frac{\left (4 a^3 b\right ) \operatorname{Subst}\left (\int \frac{1}{1-x^2} \, dx,x,\sin (c+d x)\right )}{d}-\frac{\left (10 a b^3\right ) \operatorname{Subst}\left (\int \left (-1-x^2+\frac{1}{1-x^2}\right ) \, dx,x,\sin (c+d x)\right )}{d}\\ &=\frac{4 a^3 b \tanh ^{-1}(\sin (c+d x))}{d}-\frac{a^4 \cos (c+d x)}{d}+\frac{12 a^2 b^2 \cos (c+d x)}{d}-\frac{3 b^4 \cos (c+d x)}{d}+\frac{a^4 \cos ^3(c+d x)}{3 d}-\frac{2 a^2 b^2 \cos ^3(c+d x)}{d}+\frac{b^4 \cos ^3(c+d x)}{3 d}+\frac{6 a^2 b^2 \sec (c+d x)}{d}-\frac{3 b^4 \sec (c+d x)}{d}+\frac{b^4 \sec ^3(c+d x)}{3 d}-\frac{4 a^3 b \sin (c+d x)}{d}+\frac{10 a b^3 \sin (c+d x)}{d}-\frac{4 a^3 b \sin ^3(c+d x)}{3 d}+\frac{10 a b^3 \sin ^3(c+d x)}{3 d}+\frac{2 a b^3 \sin ^3(c+d x) \tan ^2(c+d x)}{d}-\frac{\left (10 a b^3\right ) \operatorname{Subst}\left (\int \frac{1}{1-x^2} \, dx,x,\sin (c+d x)\right )}{d}\\ &=\frac{4 a^3 b \tanh ^{-1}(\sin (c+d x))}{d}-\frac{10 a b^3 \tanh ^{-1}(\sin (c+d x))}{d}-\frac{a^4 \cos (c+d x)}{d}+\frac{12 a^2 b^2 \cos (c+d x)}{d}-\frac{3 b^4 \cos (c+d x)}{d}+\frac{a^4 \cos ^3(c+d x)}{3 d}-\frac{2 a^2 b^2 \cos ^3(c+d x)}{d}+\frac{b^4 \cos ^3(c+d x)}{3 d}+\frac{6 a^2 b^2 \sec (c+d x)}{d}-\frac{3 b^4 \sec (c+d x)}{d}+\frac{b^4 \sec ^3(c+d x)}{3 d}-\frac{4 a^3 b \sin (c+d x)}{d}+\frac{10 a b^3 \sin (c+d x)}{d}-\frac{4 a^3 b \sin ^3(c+d x)}{3 d}+\frac{10 a b^3 \sin ^3(c+d x)}{3 d}+\frac{2 a b^3 \sin ^3(c+d x) \tan ^2(c+d x)}{d}\\ \end{align*}
Mathematica [B] time = 6.27546, size = 1017, normalized size = 3.7 \[ -\frac{\left (3 a^4-42 b^2 a^2+11 b^4\right ) (a+b \tan (c+d x))^4 \cos ^5(c+d x)}{4 d (a \cos (c+d x)+b \sin (c+d x))^4}+\frac{a b \left (a^2-b^2\right ) \sin (3 (c+d x)) (a+b \tan (c+d x))^4 \cos ^4(c+d x)}{3 d (a \cos (c+d x)+b \sin (c+d x))^4}+\frac{\left (a^4-6 b^2 a^2+b^4\right ) \cos (3 (c+d x)) (a+b \tan (c+d x))^4 \cos ^4(c+d x)}{12 d (a \cos (c+d x)+b \sin (c+d x))^4}-\frac{2 \left (2 a^3 b-5 a b^3\right ) \log \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right ) (a+b \tan (c+d x))^4 \cos ^4(c+d x)}{d (a \cos (c+d x)+b \sin (c+d x))^4}+\frac{2 \left (2 a^3 b-5 a b^3\right ) \log \left (\cos \left (\frac{1}{2} (c+d x)\right )+\sin \left (\frac{1}{2} (c+d x)\right )\right ) (a+b \tan (c+d x))^4 \cos ^4(c+d x)}{d (a \cos (c+d x)+b \sin (c+d x))^4}+\frac{b^4 \sin \left (\frac{1}{2} (c+d x)\right ) (a+b \tan (c+d x))^4 \cos ^4(c+d x)}{6 d \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right )^3 (a \cos (c+d x)+b \sin (c+d x))^4}+\frac{\left (36 a^2 b^2 \sin \left (\frac{1}{2} (c+d x)\right )-17 b^4 \sin \left (\frac{1}{2} (c+d x)\right )\right ) (a+b \tan (c+d x))^4 \cos ^4(c+d x)}{6 d \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right ) (a \cos (c+d x)+b \sin (c+d x))^4}+\frac{\left (17 b^4 \sin \left (\frac{1}{2} (c+d x)\right )-36 a^2 b^2 \sin \left (\frac{1}{2} (c+d x)\right )\right ) (a+b \tan (c+d x))^4 \cos ^4(c+d x)}{6 d \left (\cos \left (\frac{1}{2} (c+d x)\right )+\sin \left (\frac{1}{2} (c+d x)\right )\right ) (a \cos (c+d x)+b \sin (c+d x))^4}-\frac{a b \left (5 a^2-9 b^2\right ) \sin (c+d x) (a+b \tan (c+d x))^4 \cos ^4(c+d x)}{d (a \cos (c+d x)+b \sin (c+d x))^4}-\frac{b^2 \left (17 b^2-36 a^2\right ) (a+b \tan (c+d x))^4 \cos ^4(c+d x)}{6 d (a \cos (c+d x)+b \sin (c+d x))^4}+\frac{\left (b^4+12 a b^3\right ) (a+b \tan (c+d x))^4 \cos ^4(c+d x)}{12 d \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right )^2 (a \cos (c+d x)+b \sin (c+d x))^4}+\frac{\left (b^4-12 a b^3\right ) (a+b \tan (c+d x))^4 \cos ^4(c+d x)}{12 d \left (\cos \left (\frac{1}{2} (c+d x)\right )+\sin \left (\frac{1}{2} (c+d x)\right )\right )^2 (a \cos (c+d x)+b \sin (c+d x))^4}-\frac{b^4 \sin \left (\frac{1}{2} (c+d x)\right ) (a+b \tan (c+d x))^4 \cos ^4(c+d x)}{6 d \left (\cos \left (\frac{1}{2} (c+d x)\right )+\sin \left (\frac{1}{2} (c+d x)\right )\right )^3 (a \cos (c+d x)+b \sin (c+d x))^4} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.059, size = 412, normalized size = 1.5 \begin{align*}{\frac{{b}^{4} \left ( \sin \left ( dx+c \right ) \right ) ^{8}}{3\,d \left ( \cos \left ( dx+c \right ) \right ) ^{3}}}-{\frac{5\,{b}^{4} \left ( \sin \left ( dx+c \right ) \right ) ^{8}}{3\,d\cos \left ( dx+c \right ) }}-{\frac{16\,{b}^{4}\cos \left ( dx+c \right ) }{3\,d}}-{\frac{5\,{b}^{4}\cos \left ( dx+c \right ) \left ( \sin \left ( dx+c \right ) \right ) ^{6}}{3\,d}}-2\,{\frac{{b}^{4}\cos \left ( dx+c \right ) \left ( \sin \left ( dx+c \right ) \right ) ^{4}}{d}}-{\frac{8\,{b}^{4}\cos \left ( dx+c \right ) \left ( \sin \left ( dx+c \right ) \right ) ^{2}}{3\,d}}+2\,{\frac{{b}^{3}a \left ( \sin \left ( dx+c \right ) \right ) ^{7}}{d \left ( \cos \left ( dx+c \right ) \right ) ^{2}}}+2\,{\frac{{b}^{3}a \left ( \sin \left ( dx+c \right ) \right ) ^{5}}{d}}+{\frac{10\,{b}^{3}a \left ( \sin \left ( dx+c \right ) \right ) ^{3}}{3\,d}}+10\,{\frac{{b}^{3}a\sin \left ( dx+c \right ) }{d}}-10\,{\frac{{b}^{3}a\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{d}}+6\,{\frac{{a}^{2}{b}^{2} \left ( \sin \left ( dx+c \right ) \right ) ^{6}}{d\cos \left ( dx+c \right ) }}+16\,{\frac{{a}^{2}{b}^{2}\cos \left ( dx+c \right ) }{d}}+6\,{\frac{{a}^{2}{b}^{2}\cos \left ( dx+c \right ) \left ( \sin \left ( dx+c \right ) \right ) ^{4}}{d}}+8\,{\frac{{a}^{2}{b}^{2}\cos \left ( dx+c \right ) \left ( \sin \left ( dx+c \right ) \right ) ^{2}}{d}}-{\frac{4\,b{a}^{3} \left ( \sin \left ( dx+c \right ) \right ) ^{3}}{3\,d}}-4\,{\frac{b{a}^{3}\sin \left ( dx+c \right ) }{d}}+4\,{\frac{b{a}^{3}\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{d}}-{\frac{\cos \left ( dx+c \right ) \left ( \sin \left ( dx+c \right ) \right ) ^{2}{a}^{4}}{3\,d}}-{\frac{2\,{a}^{4}\cos \left ( dx+c \right ) }{3\,d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.14764, size = 294, normalized size = 1.07 \begin{align*} \frac{{\left (\cos \left (d x + c\right )^{3} - 3 \, \cos \left (d x + c\right )\right )} a^{4} - 2 \,{\left (2 \, \sin \left (d x + c\right )^{3} - 3 \, \log \left (\sin \left (d x + c\right ) + 1\right ) + 3 \, \log \left (\sin \left (d x + c\right ) - 1\right ) + 6 \, \sin \left (d x + c\right )\right )} a^{3} b - 6 \,{\left (\cos \left (d x + c\right )^{3} - \frac{3}{\cos \left (d x + c\right )} - 6 \, \cos \left (d x + c\right )\right )} a^{2} b^{2} +{\left (4 \, \sin \left (d x + c\right )^{3} - \frac{6 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} - 15 \, \log \left (\sin \left (d x + c\right ) + 1\right ) + 15 \, \log \left (\sin \left (d x + c\right ) - 1\right ) + 24 \, \sin \left (d x + c\right )\right )} a b^{3} +{\left (\cos \left (d x + c\right )^{3} - \frac{9 \, \cos \left (d x + c\right )^{2} - 1}{\cos \left (d x + c\right )^{3}} - 9 \, \cos \left (d x + c\right )\right )} b^{4}}{3 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.13296, size = 528, normalized size = 1.92 \begin{align*} \frac{{\left (a^{4} - 6 \, a^{2} b^{2} + b^{4}\right )} \cos \left (d x + c\right )^{6} - 3 \,{\left (a^{4} - 12 \, a^{2} b^{2} + 3 \, b^{4}\right )} \cos \left (d x + c\right )^{4} + 3 \,{\left (2 \, a^{3} b - 5 \, a b^{3}\right )} \cos \left (d x + c\right )^{3} \log \left (\sin \left (d x + c\right ) + 1\right ) - 3 \,{\left (2 \, a^{3} b - 5 \, a b^{3}\right )} \cos \left (d x + c\right )^{3} \log \left (-\sin \left (d x + c\right ) + 1\right ) + b^{4} + 9 \,{\left (2 \, a^{2} b^{2} - b^{4}\right )} \cos \left (d x + c\right )^{2} + 2 \,{\left (2 \,{\left (a^{3} b - a b^{3}\right )} \cos \left (d x + c\right )^{5} + 3 \, a b^{3} \cos \left (d x + c\right ) - 2 \,{\left (4 \, a^{3} b - 7 \, a b^{3}\right )} \cos \left (d x + c\right )^{3}\right )} \sin \left (d x + c\right )}{3 \, d \cos \left (d x + c\right )^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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